Arithmatical - Problems on Trains

DIRECTIONS : Problems based on Trains.
21. Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively The ratio of their speeds is
  A.  2 : 3
  B.  4 : 3
  C.  6 : 7
  D.  9 : 16
Solution
Let us name the trains
as A and B.
= (A'S speed) : (B's speed)
=√b : √a
= √16 : √9
= 4 : 3
22. Two trains 100 meters and 120 meters long aer running in the same diredtion with speeds of 72 km/hr and 54 km/hr. In how much time will the first train cross the seconds?
  A.  40 sec
  B.  44 sec
  C.  46 sec
  D.  48 sec
Solution
Relative Speed of trains= (72 - 54) km/hr
= 18 km/hr
= (18 x 5 /18) km/hr
= 5 m /sec.
Time taken to cover= (100 + 120) m/sec
= (220 / 5 ) sec
= 44 sec

23. A train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?
  A.  12 sec
  B.   15 sec
  C.  16 sec
  D.  18 sec
Solution
Speed of the train = (59 + 7) kmph
= (66 x 5 /18) m/sec
= (55 / 3) m/sec.
Time taken by it cover 220m at (55/3) m/sec = (220 x 3/55) sec
= 12 sec.
24. A train 360 m long is running at a speed of 45 km/hr. In what time it will it pass a bridge 140 m long?
  A.  40 sec
  B.  42 sec
  C.  45 sec
  D.  48 sec
Solution
speed =(45 + 5 / 18)m/sec
=(25 / 2)m/sec
Total distance covered =(360 + 140 )m
=500 m
Required time =(500 x 2 / 25)sec
= 40 sec.
25. A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is
  A.  90 m
  B.  100 m
  C.  120 m
  D.  140 m
Solution
Speed = (12 / 10 x 60)km/hr
= (72 x 5/18) m/sec
= 20 m/sec.
Length of the train = (speed x time )
= (20 x 6)m
= 120 m.
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