Arithmatical - True Discount

DIRECTIONS : Problems based on True discounts.
6. The present worth of Rs. 2310 due 2 1/2 years hence, the rate of interest being 15% per annum, is
  A.  Rs.1680
  B.  Rs.1750
  C.  Rs.1840
  D.  Rs.1443.75
Solution
P.W.= Rs= [100 x 2310/100 +(15 x5/2)]
= Rs. 1680.
7. The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due iss
  A.  6 months
  B.  8 months
  C.  9 months
  D.  10 months
Solution
P.W= Rs. (1760 -160)
= Rs.1600
S.I. on Rs. 1600 at 12% is Rs. 160.
Time= (100 x 160/1600 x 12)
=5/6 years.
=(5/6 x12) months
=10 months.
8. Find the present worth of Rs. 930 due 3 years hence at 8% per annum. Also find the discount?
  A.  Rs.500
  B.  Rs.625
  C.  Rs. 750
  D.  Rs. 890
Solution
P.W=100 x Amount/100+(RxT)
= Rs[100x930/100+(8x3)]
= Rs.(100x930/124)
= Rs.750.
9. A man purchased a cow for Rs. 3000 and sold it the same day for Rs.3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of
  A.  0%
  B.  5%
  C.  7.5%
  D.  10%
Solution
C.P = Rs. 3000.
S.P=Rs[3600x100/100+(10x2)]
=3000
So, Gain is 0 %.
10. If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is
  A.  Rs.768
  B.  Rs.968
  C.  Rs.1960
  D.  Rs.2400
Solution
P.W=100 x T.D/R x T
= 100 x 168/14 x 2
= 600.
Sum= (P.W + T.D)
Rs. (600 + 168)
= Rs. 768.
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