Arithmatical  Problems on Ages
Solved Examples
1.  The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice athe age of the son. Find the present age of the father. 

Sol. Let the son’s present age be x years. Then, father’s present age = (3x + 3) years.  
Therefore (3x + 3 + 3) = 2 (x + 3) + 10 ‹=› 3x + 6 = 2x + 16 ‹=› x = 10 

Hence, father’s present age = (3x + 3) = (3 x 10 + 3) years = 33 years. 