Arithmatical - Compound Interest
DIRECTIONS : Problems based on Interest.
| 13. |
In what time will Rs.1000 become Rs.1331 at 10% per annum compounded annually? |
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A. 2 years |
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B. 3 years |
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C. 4 years |
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D. 7 years |
| Solution |
| Principal | = Rs.1000; |
| Amount | = Rs.1331; |
| Rate | = Rs.10%p.a. |
| Let the time be n years.Then |
| [1000(1+10/100)Λn;] |
| = 1331. |
| = (1331/1000) |
| = (11/10)³ |
| Therefore n = 3 years. |
|
| 14. |
The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half yearly is |
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A. 6.06% |
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B. 6.07% |
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C. 6.08% |
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D. 6.09% |
| Solution |
| Amount of Rs.100 for 1 year when compounded half yearly |
| = Rs.[100 x (1+3/100)2] |
| = Rs. 106.09%. |
| Effective rate | = (106.09 - 100)% |
| = Rs. 6.09%. |
|
| 15. |
What will be the difference between simple interest and compound interest @10% per annum on a sum of Rs. 1000 after 4 years? |
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A. Rs. 31 |
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B. Rs. 32.10 |
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C. Rs. 40.40 |
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D. Rs. 64.10 |
| Solution |
| S.I. | =Rs(1000x10x4 / 100) |
| = Rs.400. |
| C.I. | =Rs.[1000x(1x10/100)4-1000] |
| = Rs. 464.10 |
| ∴ Difference = Rs.(464.10 - 400) |
| = Rs. 64.10 |
|