a2zinterviews

46.	The sum of the smallest six digit number and the greatest five digit number is
	A.  201110
	B.  199999
	C.  211110
	D.  1099999

Solution

Requires sum =(100000 + 99999) =199999.

47.	In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, the divident is
	A.  4236
	B.  4306
	C.  4336
	D.  5336

Solution

Divisor = (5×46) = 230. Also. 10×Q = 230 ‹=› Q=23. And, R= 46. Dividend = (230×23+46) = 5336.

48.	A positive integer, which when added to 1000, gives a sum which is greater than when it is multiplied by 1000. This positive integer is
	A.  1
	B.  3
	C.  5
	D.  7

Solution

(1000 + N) > (1000N) Clearly, N=1.

49.	The difference between two numbers is 1365. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is
	A.  240
	B.  270
	C.  295
	D.  360

Solution

Let the smaller number be x. Then, larger number = (1365 + x)) Therefore 1365 + x ‹=›(6x+15 ‹=› 5x = 1350 ‹=› x= 270.

50.	If x is a whole number, then x²(x² - 1) is always divisible by
	A.  multiple of 12
	B.  24
	C.  12 - x
	D.  12

Solution

Putting x = 12,we get 2²(2² - 1) = 12. So, x²(x² - 1) is always divisible by 12.