a2zinterviews

13.	A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is
	A.  10√2 m
	B.  100 m
	C.  100√2 m
	D.  200 m

Solution

Let the altitude of the triangle be hïand base of each be b. Then , (½ ×b× h1) where h2 = 100 m. = h1 = 2h2 = ( 2 x 100) m = 200 m.

14.	The perimeter of a rhombus are 24 cm and 10 cm, the area and the perimeter of the rhombus is
	A.  64 sq.m
	B.  70 sq.m
	C.  78 sq.m
	D.  84 sq.m

Solution

Perimeter of the rhombus = 56 m Each side of the rhombus = 56 / 4 m = 14 m. Height of the rhombus = 5 m Area = (14 x 5) m² = 70 m²

15.	The difference of the areas of two squares drawn on two line segments of different lengths is 32 sq .cm. Find the length of the greater line segment if one is longer than the other by 2cm.
	A.  6 cm
	B.  7 cm
	C.  9 cm
	D.  11 cm

Solution

Let the lengths of the line segments be x cm and (x + 2) cm. Then (x+2)2 - x2 = 32 <=> x2+4x+4-x2 = 32 <=> 4x = 28 Therefore x = 7. Length of longer line segment = (7 + 2) cm = 9 cm.

16.	A courtyard 25 m long and 16 m broad is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is
	A.  15000
	B.  18000
	C.  20000
	D.  25000

Solution

Number of bricks = [ Area of courtyard / Area of 1 brick ] = [2500×1600 / 20×10] = 20000.