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13.	Rajan got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The age of Rajan's sister is
	A.  32 years
	B.  36 years
	C.  38 years
	D.  40 years

Solution

Let Rajan's present age be x years. Then, his age at the time of marriage =(x-8) years. Therefore x= 6/5(x-6) 5x = 6x-48 x=48. Rajan's sister's age at the time of his marriage=(x-8)-10 =(x-18)=30 Rajan's sister's present age =(30+8) = 38 years.

14.	In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is
	A.  9 years
	B.  19 years
	C.  29 years
	D.  39 years

Solution

Let B's present age = x years. Then, A's present age ‹=› (x + 9) years. ∴(x + 9) + 10 = 2 (x - 10) ‹=› x + 19 = 2x - 20 ‹=› x = 39.

15.	The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
	A.  12 years
	B.  20 years
	C.  25 years
	D.  28 years

Solution

Let the present ages of son and father be x and (60 - x) years respectively. Then, (60 - x) - 6 = 5(x - 6) = 54 - x = 5x - 30 ‹=›6x = 84 ‹=›x= 14. ∴Son's age after 6 years = (x + 6) = 20 years.